Answer:
I'm gonna go with C
Step-by-step explanation:
Don't take my word for it
Answer:
The volume of the cylinder is 120.10 square feet.
Step-by-step explanation:
Given that the radius of a cylindrical construction pipe is 1.5 ft, to determine its volume if the pipe is 17 ft long, the following calculation must be performed, knowing that the volume of a cylinder arises from multiplying the number pi by the radius at square of the cylinder, and that result by the height of the same:
3.14 x 1.5 ^ 2 x 17 = X
3.14 x 2.25 x 17 = X
7.065 x 17 = X
120.105 = X
Thus, the volume of the cylinder is 120.10 square feet.
Answer:
729
Step-by-step explanation:
9 x 9 x 9
Answer:
The volume of the water in the pool is 1,017 cubic feet
Step-by-step explanation:
we know that
The volume of a cylinder is equal to
![V=\pi r^{2} h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E%7B2%7D%20h)
we have
----> the radius is half the diameter
Remember that
![1\ ft=12\ in](https://tex.z-dn.net/?f=1%5C%20ft%3D12%5C%20in)
so
![6\ in=6/12=0.5\ ft](https://tex.z-dn.net/?f=6%5C%20in%3D6%2F12%3D0.5%5C%20ft)
To find out the height of the water, subtract 0.5 feet from the height of the swimming pool
![h=4.5-0.5=4\ ft](https://tex.z-dn.net/?f=h%3D4.5-0.5%3D4%5C%20ft)
assume
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
Find the volume of the water
![V=(3.14)(9^{2})(4)](https://tex.z-dn.net/?f=V%3D%283.14%29%289%5E%7B2%7D%29%284%29)
![V=1,017\ ft^3](https://tex.z-dn.net/?f=V%3D1%2C017%5C%20ft%5E3)
1. ∠ADC is right angle, then ![m\angle ADC=90^{\circ}.](https://tex.z-dn.net/?f=m%5Cangle%20ADC%3D90%5E%7B%5Ccirc%7D.)
2. Angles ADB and BDC are complementary, then
![m\angle ADB+m\angle BDC=m\angle ADC=90^{\circ}.](https://tex.z-dn.net/?f=m%5Cangle%20ADB%2Bm%5Cangle%20BDC%3Dm%5Cangle%20ADC%3D90%5E%7B%5Ccirc%7D.)
3. You know that ∠BDC is 32° greater than ∠ ADB. Let
then ![m\angle BDC=x+32^{\circ}.](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3Dx%2B32%5E%7B%5Ccirc%7D.)
Since
you have that
![x+x+32^{\circ}=90^{\circ},\\ \\2x=90^{\circ}-32^{\circ},\\ \\2x=58^{\circ},\\ \\x=29^{\circ}.](https://tex.z-dn.net/?f=x%2Bx%2B32%5E%7B%5Ccirc%7D%3D90%5E%7B%5Ccirc%7D%2C%5C%5C%20%5C%5C2x%3D90%5E%7B%5Ccirc%7D-32%5E%7B%5Ccirc%7D%2C%5C%5C%20%5C%5C2x%3D58%5E%7B%5Ccirc%7D%2C%5C%5C%20%5C%5Cx%3D29%5E%7B%5Ccirc%7D.)
This gives you: