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2 years ago

HELPPP ME PLEASEeeeeee

Mathematics

2 answers:

Korvikt [17]2 years ago

4 0

Answer:

4.116 × 10^8 = 411,600,000

Step-by-step explanation:

i just put it in the calculator dont get mad at me

Natalka [10]2 years ago

3 0

I haven’t done this in a while but i believe it’s c

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Plz help quick. This question is on a quiz in Edg 2020 whoever answered first will get brainliest and I will be giving 50 points

lys-0071 [83]

Answer:

A B and D

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Plz help for financial algebra

serious [3.7K]

Answer: $277.91

<u>Step-by-step explanation:</u>

The average of the 2 highest salaried quarters is:

$\dfrac{\$13,500+\$12,775}{2}=\dfrac{\$26,275}{2}=\$3,137.50$

Divide that by 26 (weeks) to find out her average weekly salary:

$\dfrac{\$3,137.50}{26}=\$505.29$

Multiply that by 55% (0.55) to calculate her weekly unemployment benefit:

$\$505.29(0.55)=\$277.908$

Round to the nearest penny --> $277.91

4 0

2 years ago

Could someone help me with this im so confused

Arlecino [84]

Ok so basically the number by the X is your slope (m) and the other number is your y-intercept (b) so for example the first question your slope (m) 2/3 and your y-intercept (b) -2

6 0

2 years ago

HELPP!!

SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0

3 years ago

Janet deposited $9,600 into an account that pays 4.4 interest, compounded daily. At the end of nine months, how much interest ha

neonofarm [45]

bearing in mind that 9 months is not even a year, but since there are 12 months in a year, then 9 months is really 9/12 years.

$\bf ~~~~~~ \stackrel{\textit{daily}}{\textit{Continuously}} \textit{Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$9600\\ r=rate\to 4.4\%\to \frac{4.4}{100}\dotfill &0.044\\ t=years\to \frac{9}{12}\dotfill &\frac{3}{4} \end{cases} \\\\\\ A=9600e^{0.044\cdot \frac{3}{4}}\implies A=9600e^{0.033}\implies A\approx 9922.09 \\\\\\$

$\bf \stackrel{\textit{interest earned}}{9922.09-9600\implies 322.09}$

5 0

3 years ago