<h3>
Answer: 65</h3>
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Explanation:
We'll need to compute the difference quotient. In this case, we need to find what is equal to. It's called a difference quotient because there's a subtraction in the numerator (aka "difference") and we're dividing to form the quotient.
The idea is that as h approaches 0, then that expression I wrote will approach the derivative we're after. Keep in mind that h will technically never get to 0 itself. It only gets closer and closer.
Anyways, let's compute first
Then we'll subtract off g(t)
A very important thing to notice: the terms that don't have any 'h's in them have been canceled out (eg: 5t^2 combined with -5t^2 added to 0). Why is this important? It's because we need to factor 'h' out and we'll have a pair of 'h's cancel like so
The left hand side cannot have h = 0, or else we have a division by zero error. But if we approached 0 (not actually getting there), then the expression 5h+10t+5 will approach 5(0)+10t+5 = 10t+5
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In short: The derivative of is
In terms of symbols,
Later on in calculus, you'll learn a shortcut so you won't have to compute the difference quotient every time you need a derivative. Refer to the power rule for more information.
After we find the derivative, it's as straight forward as plugging in t = 6 to compute g ' (6)
Side note: This tells us that the slope of the tangent line is m = 65 when t = 6. In other words, this line is tangent to g(t) when t = 6, and this particular tangent line has slope m = 65.
Answer:
Both fractions are already in the simplest form.
Portuguese translation: Ambas as frações já estão na forma mais simples.
9514 1404 393
Answer:
a: 0; b: 1; c: 1; d: ∞; e: 0; f: ∞
Step-by-step explanation:
Simplify the expressions to put the left and right in the same form. Then compare. If the x-coefficients are the same, there will be 0 or ∞ solutions. If they are different, there will be 1 solution.
If the x-coefficients are the same, look at the constants. If they are different, there will be 0 solutions. If they are the same, there will be ∞ solutions.
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a) -2x -10 = -6x +4x -8 ⇒ -2x -10 = -2x -8 . . . . 0 solutions
b) 0.8x -4.8 = -0.5x +3.4 . . . . 1 solution
c) -1/4x -7/2 = -3x -4 . . . . 1 solution
d) 2x -8 +x = 3x -6 -2 ⇒ 3x -8 = 3x -8 . . . . ∞ solutions
e) 3 -2/5x -12/5 = 2 -2/5x ⇒ -2/5x +3/5 = -2/5x +2 . . . . 0 solutions
f) 6x -6 +21 = 6x +15 ⇒ 6x +15 = 6x +15 . . . . ∞ solutions
Since x is on the right side of the equation, switch the sides so it is on the left side of the equation.<span><span>6<span>x<span>−3</span></span></span>=<span>136</span></span>Create equivalent expressions in the equation that all have equal bases.<span><span>6<span>x<span>−3</span></span></span>=<span>6<span>−2</span></span></span>Since the bases are the same, then two expressions are only equal if the exponents are also equal.<span><span>x<span>−3</span></span>=<span>−2</span></span>Move all terms not containing x to the right side of the equation..Since <span>−3</span> does not contain the variable to solve for, move it to the right side of the equation by adding 3 to both sides.<span>x=<span>3<span>−2</span></span></span>Subtract 2 from 3 to get 1.<span>x=<span>1</span></span>