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nordsb [41]
3 years ago
10

Based on the graph below, determine the zeros of the functon

Mathematics
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

-3,-2,1

Step-by-step explanation:

its what x is when y=0

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ATTENTION
finlep [7]

Here!

<h2>The answer is Option A!</h2>

(x + 2 \sqrt{3} i)(x - 2 \sqrt{3}i )

<h3>Why so??</h3>

Let's see what complex numbers are!

(x + 2  \sqrt{3 }i  )(x - 2 \sqrt{3}i ) \\  =  {x}^{2}  - 2 \sqrt{3} x + 2 \sqrt{3} x -  {(2 \sqrt{3} i)}^{2}  \\  =  {x}^{2}  -  {(2 \sqrt{3}i) }^{2}

Now we know,

{i}^{2}  =  - 1

So!

=  {x}^{2}  - 12 \times(  - 1)

=  {x}^{2}  + 12

And thus we get the answer!

3 0
3 years ago
What’s the area of the shape?
Kaylis [27]

Answer:

A: 72 square feet

Step-by-step explanation:

Hopefully this helps!

7 0
3 years ago
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How can the Pythagorean Identity be used to find sin θ, cos θ, or tan θ and the quadrant location of the angle?
Archy [21]

First lets see the pythagorean identities

sin^2 \Theta + cos^2 \Theta =1

So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is

sin^2 \Theta = 1-cos^2 \Theta => sin \theta = \pm \sqrt{1-cos^2 \Theta}

Now we need to check the sign of sin theta

First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.

So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .

5 0
3 years ago
Help
garik1379 [7]
What happened in the 1920s that greatly lowered the price of cars (automobiles) and other consumer products?
3 0
3 years ago
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Please answer it fast​
Afina-wow [57]

Answer:

0 and - 10

-4 and - 15

Step-by-step explanation:

5 + (-1) = 5 - 1 = 4

Which does lie between

  • 0 and - 10
  • -4 and - 15

Hope it helps you in your learning process

8 0
3 years ago
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