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3 years ago

8

The storage space of a moving truck is in the shape of a rectangular prism. The dimensions are 6 feet wide, 10 feet long, and 6

feet tall. What is the volume of the truck's storage space?

2 answers:

Leona [35]3 years ago

4 0

V=l*w*h
v=10*6*6
The volume is 360 cubic feet.

Karolina [17]3 years ago

3 0

Forgive if I am wrong, but I think the answer is 360 feet cubed

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Talia uses 10 strawberries and 4 oranges to make 8 servings of fruit salad. How many strawberries for 12 servings?

gayaneshka [121]

For 8 servings, Talia uses strawberries = 10
For 1, it is = 10/8

Now, for 12 servings, it would be: 10/8 * 12 = 10/2 * 3 = 5 * 3 = 15

In short, Your Answer would be 15 strawberries

Hope this helps!

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4 years ago

Solve the system of the linear equation by adding or subtracting.

Natali [406]

X=1 and y=-2

In ordered pairs it would be (1,0) and (0,-2)

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3 years ago

5) What is the distance between the points (3,-5) and (5,6)?

Afina-wow [57]

B 11.2 Have a good day :)

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3 years ago

What are the zeros of the polynomial function f(x) = x3 - 2x2 - 24x? (1 point)

vodka [1.7K]

f(x) = x³ - 2x² - 24x

x³ - 2x² - 24x = 0

x(x² - 2x - 24) = 0

x = 0

x² - 2x - 24 = 0

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Delta = (-2)² - 4 * 1 * (-24) = 4 + 96 = 100

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3 years ago

a study timed left-handed and right-handed people to see how long it took them to hit a buzzer. the data is shown below: the six

Effectus [21]

The z or t score to be used is (0.422,0.978)

How to find the critical value ?

Critical probability (p*) = 1 - (Alpha / 2), where Alpha is equal to 1 - (the confidence level / 100), is the unit statisticians use to determine the margin of error within a set of data in statistics.

The critical value for α = 0.13 is $z_{c} = \frac{z_{1} - \alpha }{2}$

The corresponding confidence interval is computed as shown below

$CI = (X1_{1} - X_{2}- z_{c} \sqrt{\frac{a_{1}^{2}}{n_{1} } + \frac{a_{2}^{2}}{n_{2} }} , X1_{1} - X_{2}+z_{c} \sqrt{\frac{a_{1}^{2}}{n_{1} } + \frac{a_{2}^{2}}{n_{2} }} )$

$CI = (2.1 - 1.4- 1.514\sqrt{\frac{1^{2}}{37 } + \frac{0.5_{2}^{2}}{38 }} , 2.1 - 1.4 + 1.514 \sqrt{\frac{1^{2}}{37 } + \frac{0.5^{2}}{38 }} )$

CI = (0.422, 0.978)

0.422< mu1 - mu 2 < 0.978

To learn more about finding the critical value from the given link

brainly.com/question/14040224

#SPJ4

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1 year ago