The product of two consecutive negative integers is 600. What is the value of the lesser integer?

2 answers:

8 0

X ·( x + 1 ) = 600
x² + x = 600
x² + x - 600 = 0
$x_{12} = \frac{-1+/- \sqrt{1+2400} }{2}= \frac{-1+/- \sqrt{2401} }{2}= \\ =\frac{-1+/-50}{2}$
x = ( - 1 - 49 ) / 2 = - 50 : 2 = - 25
x = - 25, x + 1 = - 24
( - 25 ) · ( - 24 ) = 600
Answer:
C ) - 25

Likurg_2 [28]3 years ago

5 0

x ·( x + 1 ) = 600

x² + x = 600

x² + x - 600 = 0

x_{12} = \frac{-1+/- \sqrt{1+2400} }{2}= \frac{-1+/- \sqrt{2401} }{2}= \\ =\frac{-1+/-50}{2}

x = ( - 1 - 49 ) / 2 = - 50 : 2 = - 25

x = - 25, x + 1 = - 24

( - 25 ) · ( - 24 ) = 600

Answer:

C ) - 25

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