3 years ago

If F(x) =5x/3 +5

1 answer:

7 0

Answer:

$f^{-1}(x)=\frac{3(x-5)}{5}$

Step-by-step explanation:

$f(x)=y=\frac{5x}{3}+5\\y-5=\frac{5x}{3}\\3(y-5)=5x\\x=\frac{3(y-5)}{5}\\ => f^{-1}(x)=\frac{3(x-5)}{5}$

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