3 years ago

Help me please ThankYou !!

Mathematics

1 answer:

matrenka [14]3 years ago

3 0

My answer would be A.

You might be interested in

Select the correct answer

Agata [3.3K]

Answer:

f(-7)=12

Step-by-step explanation:

f(-7)= 5-(-7)

f(-7)=5+7

f(-7)=12

7 0

3 years ago

Read 2 more answers

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. A = 50Á, b

Gnesinka [82]

5580 if i did my math right thats the answer

4 0

3 years ago

Read 2 more answers

A line goes through the points (-4,6) and (-2,3). A line perpendicular to<br> that line is:

gulaghasi [49]

Answer: A line with a slope of 2

Step-by-step explanation: the slope of the line is -1/2 so the negative reciprcal of the slope is 2 (It would be perpendicular to it)

i used m=y2-y2/x2-x1 to figure ou the slope and -(x/y) as the negative reciprcal for the perpendicular line.

5 0

3 years ago

The Midpoint of Ab is M (3,-1). If the. coordinates of A are (5,1) what are the coordinates of B ?

Lana71 [14]

The endpoints coordinates (b) should be (1,-3)

6 0

3 years ago

When expressing sets, you may write "inf" for infinity and "U" for union.

GarryVolchara [31]

Answer:

The complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

Step-by-step explanation:

The given set in interval notation is

(−5,6]

It means the set is defined as

$A=\{x|x\in R,-5$

If B is a set and U is a universal set, then complement of set B contains the elements of universal set but not the elements of set B.

Here, universal set is R, the set set of all real numbers.

$U=\{x|x\in R\}$

The complement of the given set is

$A^c=U-A$

$A^c=\{x|x\in R,-\infty$

Complement of the given set in interval notation is

$A^c=(-\infty,-5]\cup(6,\infty)$

Therefore the complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

3 0

3 years ago