3 years ago

School x and school y compete in a competition

1 answer:

7 0

So, I would set this up as a system of equations problem. x=y+8 and x=3y Then, you can substitute one equation for x. y+8=3y Next, you’ll want to solve for y.

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What is the solution to log (9x)-log2^3= 3?

olga_2 [115]

For this case we have that by definition of properties logarithm is met:

$log_ {b} (x) -log_ {b} (y) = log_ {b} (\frac {x} {y})$

So, rewriting the expression we have:

$log (\frac {9x} {2 ^ 3}) = 3\\log (\frac {9x} {8}) = 3$

By definition of logarithm we have to:

$log_ {b} (x) = y$ is equivalent to $b ^ y = x$

So:

$10 ^ 3 = \frac {9x} {8}\\9x = 8 * 10 ^ 3\\9x = 8 * 1000\\9x = 8000\\x = \frac {8000} {9}$

ANswer:

$x = \frac {8000} {9}$

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The answer is a, 21. 21x3 is 63. 63 + 1 = 64.

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The vertex is located at (-1,-9)

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3 years ago

If you want another good app for math I suggest Conects

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Thank you so much for the tip

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I NEED HELP WITH THIS QUESTION/PROBLEM

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