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tatiyna
3 years ago
14

School x and school y compete in a competition

Mathematics
1 answer:
kumpel [21]3 years ago
7 0
So, I would set this up as a system of equations problem. x=y+8 and x=3y Then, you can substitute one equation for x. y+8=3y Next, you’ll want to solve for y.
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Two numbers that have a difference of 8.
BlackZzzverrR [31]

Answer:

16/2 = 8

24/3 = 8

7 0
3 years ago
Read 2 more answers
30 points!
slamgirl [31]

Answer:

Hello, Your answer is 1.02$

Step-by-step explanation:

First of all, let's calculate the total amount payed by Veena for her meal:  t =9.25$ + 4.35$ =13.6$ The tax was 7.5%, which corresponds to a fraction of 7.5% =7.5/100 therefore, the amount of tax payed by Veena for her meal is   tax = 7.5/100 . t = 7.5/100 (13.6$) =1.02$<em> Hope This Helps!</em>

8 0
3 years ago
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Dan had $10. He bought x pencils, each costing y cents .How much money did Dan have left?
tekilochka [14]

Answer:

Dan bought 3 pencils and each pencil cost 5 cents.You know logically that it took 15 cents. He would need one nickle for each pencil he bought, or 3 nickles.

6 0
4 years ago
PLEASEEE HELP solving this problem!
tensa zangetsu [6.8K]
There you go I hope this helps.

3 0
3 years ago
Factor the algebraic expression below in terms of a single trigonometric function. sin 2x + sin x - 2
Pie

Answer:

The factored form is (sin x +2)(sin x-1)

Step-by-step explanation:

We have been given the trigonometric function \sin^2 x +\sinx-2

We can factor this by AC method. In AC method we multiply the term a and c and then write the middle term b in such a way that the sum/difference is equal to the product 'ac'

Using the method, we can write sinx as 2sinx -sinx

\sin^2 x +2\sinx-\sin x-2

Now, we group the first two terms and the last two terms

(\sin^2 x +2\sinx)+(-\sin x-2)

Now, we take GCF from each group

\sin x(\sin x +2)-1(\sin x+2)

Factor out (sinx+2)

(\sin x +2)(\sin x-1)

Therefore, the factored form is (sin x +2)(sin x-1)

7 0
4 years ago
Read 2 more answers
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