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3 years ago

Find the area of the figure shown below and type your result in the empty box.

Mathematics

1 answer:

lianna [129]3 years ago

5 0

Answer:

did u forget to add the actual question

Step-by-step explanation:

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Help quick I'm desperate

NeTakaya

Answer:

I am sorry but I do not know

Step-by-step explanation:

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3 years ago

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The base of a 12-foot ladder is 5 feet from a building. To the nearest degree, what angle does the ladder make with the ground?

hoa [83]

Cos x=5/12. Solve for x which is 65.37 degrees.

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3 years ago

If a right angled triangle has 3 sides a,b and c when a=3,b=6 ,what is the value of c?

Nataliya [291]

Answer:

c = 3√5 ≈ 6.708

Step-by-step explanation:

Use the Pythagorean Theorem because this is a right triangle.

a^2 + b^2 = c^2

3^2 + 6^2 = c^2

9 + 36 = c^2

45 = c^2

√45 = c

c = 3√5 ≈ 6.708

5 0

3 years ago

The total bill for drinks and a pizza for three people is $14.90 before tax. The group wants to leave a 15% tip on the cost of t

andreyandreev [35.5K]

Answer:

$2.24

Step-by-step explanation:

Since we are trying to find a percentage of something, we can multiply whatever we're trying to find a percentage from by 0.X where X is equal to the number of the percentage. So in this case it's 15%. We can multiply $14.90 by 0.15 and we get 2.23500. Since we cannot have 2.235 dollars, we must round up decimal places.

The tip would be 2 dollars and 24 cents. ($2.24).

5 0

3 years ago

Situation:

Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

Given formula:

$\sf N=N_0e^{-kt}$

$\sf N_0$ = initial mass (at time t=0)
N = mass (at time t)
k = a positive constant
t = time (in days)

Given values:

$\sf N_0$ = 11 g
k = 0.125

Half-life: The time required for a quantity to reduce to half of its initial value.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

$\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}$

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

5 0

2 years ago

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Find the area of the figure shown below and type your result in the empty box.​

Find the area of the figure shown below and type your result in the empty box.