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Rashid [163]
3 years ago
15

Does the reference point selected for the properties of a substance have any effect on thermodynamic analysis? Why?

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.

Step-by-step explanation:

Consider the provided information.

We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.

The answer for this question is No.

The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.

Because in thermodynamic analysis we are deal with the change in the properties.

If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.

Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.

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Please help I need to solve this problem and I just need the answer little bit of explanation too
bija089 [108]

Answer:

-1288

Step-by-step explanation:

replace x with -7 because (x= -7) and the rest is a simple maths

3 0
3 years ago
The sides of a right triangle have a relationship as depicted below, where x is the length of the longer leg in inches.
Ratling [72]
The equation to represent the area of the triangle would be:
y = 1/2(x²) - (7/2)x

The equation to represent the perimeter of the triangle would be:
y = 3x - 6

The solutions to the system would be (12, 30) or (1, -3).  The only viable solution is (12, 30).

Explanation
The area of a triangle is found using the formula
A = 1/2bh

For our triangle, b = x and h = x-7, so we have:
A = 1/2(x)(x-7)
A = 1/2(x²-7x)
A = 1/2(x²) - (7/2)x

We will replace A with y, so we have:
y = 1/2(x²) - (7/2)x

The perimeter of a triangle is found by adding together all sides, so we have:
P = (x-7) + x + (x+1)

Combining like terms we get:
P = 3x - 6

We will replace P with y, so we have:
y = 3x - 6

Since both equations have y isolated on one side, it will be easy to use substitution to solve the system:

3x - 6 = 1/2(x²) - (7/2)x

It's easier to work with whole numbers, so we will multiply everything by 2:
6x - 12 = x² - 7x

We want all of the variables on one side, so we will subtract 6x:
6x - 12 - 6x = x² - 7x - 6x
-12 = x² - 13x

When solving quadratics, we want the equation equal to 0, so we will add 12:
-12+12 = x² - 13x + 12
0 = x² - 13x + 12

This is easy to factor, as there are factors of 12 that sum to -13; -12(-1) = 12 and -12+-1 = -13:
0 = (x-12)(x-1)

Using the zero product property, we know that either x-12=0 or x-1=0; therefore x=12 or x=1.

Putting these back into our equation for perimeter (the simplest one) we have:
y = 3(12)-6 = 36-6 = 30; (12, 30);
y = 3(1) - 6 = 3 - 6 = -3; (1, -3)

We cannot have a negative perimeter, so the only viable solution is (12, 30).
8 0
2 years ago
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natima [27]
Find the vertex form Y=3(x+3^2-34
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Arnold ran 50 feet. Which equation can be used to determine c Arnold’s total distance in cm if 1 inch is equal to 2.54 centimete
bagirrra123 [75]

Answer:

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Step-by-step explanation:

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Answer:

X≤3

Step-by-step explanation:

This is because the arrow is moving down the number line

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