Answer:
3.5
Step-by-step explanation:
Answer:
Top Left
I sincerely hope this is right and that you get g really good mark ;)
The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers
two consecutive even integers: n, n+2
next two consecutive even integers n+4, n+6
n+(n+2) >= 7+1/2(n+4 +n+6)
combine like terms
2n+2 >= 7 +1/2(2n+10)
distribute 1/2
2n+2 >= 7+n+5
2n+2>= n+12
subtract n from each side
n+2>= 12
subtract 2 from each side
n>10
4 integers : 10, 12 ,14, 16
Answer:
9a+12
Step-by-step explanation:
The perimeter is the sum of the side lengths, so is ...
6a + a + 4 + 8 + 2a
= a(6 +1 +2) + (4 +8)
= 9a +12
