The temperature was -14°F at 8 a.m.
At noon is was 10 degrees warmer - the temperature increase was 10°F
-14°F + 10°F = -4°F
The tempertaure increase between noon and 4 p.m. was twice the previous increase in temperature, which was 10°F.
10°F x 2 = 20°F
We want to know the temperature at 4 p.m. so we just add it up to the previous result.
-4°F + 20°F = 16°F
16°F is the correct answer
Answer:
1.
2.543.6
Step-by-step explanation:
We are given that
y(0)=200
Let y be the number of bacteria at any time
=Number of bacteria per unit time
Where k=Proportionality constant
2.
,y'(0)=100
Integrating on both sides then, we get
We have y(0)=200
Substitute the values then , we get
Substitute the value of C then we get
Differentiate w.r.t
Substitute the given condition then, we get
Substitute t=2
Then, we get 
e=2.718
Hence, the number of bacteria after 2 hours=543.6
Step-by-step explanation:
6/2=3
Hope that helps :)
Answer:
x4+7x3-2x2-9x-3 remainder -10
or we could write it as
x4+7x3-2x2-9x-3 - 10/(x+8)
Step-by-step explanation:
x+8 ) x5+15x4+54x3−25x2−75x−34 (x4+7x3-2x2-9x-3 <--- Quotient.
x5+ 8x4
7x4+54x3
7x4+56x3
-2x3-25x2
-2x3-16x2
-9x2-75x
-9x2-72x
-3x-34
-3x-24
-10 <--- Remainder.
