by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
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which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Step-by-step explanation:
it clearly consists of 2 rectangles and 1 triangle (as you tried correctly to point out by drawing the separating lines).
we only need to calculate all 3 areas and add them up for the total.
the area of a rectangle is
length × width
so, in our 2 cases we have
6 × 2 = 12 km²
5 × (3 + 2 + 3) = 5×8 = 40 km²
the area of a triangle is
baseline × height / 2
in case of a right-angled triangle the 2 sides enclosing the 90° angle can be used as baseline and height.
so, in our case
6 × (5 + 2 + (3 + 2 + 3 - 2)) / 2 = 6×(7 + 6)/2 = 3×13 = 39 km²
in total, the whole area is
12 + 40 + 39 = 91 km²
3/7 is the correct awnser as u can see because connie has 4 choclate cookies and kevien bought 4 brownies and luis bought 6 sugar cookies and in the simplest form the fraction would be 3/7.
Answer:
11.6cm
Step-by-step explanation:
a^2+b^2=c^2
11^2+b^2=16^2
121+b^2=256
b^2=135
b=11.6
V=hpir^2
SA=2pir^2+2hpir
a.
SA=2pi9^2+2*36pi9
SA=2pi81+72pi9
SA=162pi+648pi
SA=810pi in^2
b.
aprox pi=3.14
810*3.14=2542.4cm^2
c.
V=36pi9^2
V=36pi81
V=2916pi in^3
d. 3.14=pi
2916*3.14=9156.24 in^3
