The general solution of <span>y' + 2xy = (x^3) is y(x) = c1e^(-x^2)
The general solution of </span><span>ydx = (y(e^y) - 2x)dy is x = c1/(y(x))^2 + (e^y(x) ((y(x))^2 - 2y(x) + 2)/(y(x))^2
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The general solution of<span> (dP)/(dt) + 2tP = P + 4t - 2 is P(t) = c1e^(t - t^2) + 2</span>
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
5x - y = 8 ( subtract 5x from both sides )
- y = - 5x + 8 ( multiply through by - 1 )
y = 5x - 8 ← in slope- intercept form
with slope m = 5 and y- intercept c = - 8
7x^2+x+9 - (<span>3x^2+4x-5)
= </span>7x^2 + x + 9 - 3x^2 - 4x + 5
= 4x^2 - 3x + 14
Answer: took the test and the answers are at the bottom. cheers mate :)
Step-by-step explanation:
