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Kobotan [32]
3 years ago
8

The equation k = 1.6d gives an approximate relationship between d miles and k

Mathematics
1 answer:
uranmaximum [27]3 years ago
6 0

Substituting d= 430 we get,

k = 1.6(430)

k = 688

The distance between Boise, Idaho and Reno, Nevada is 688 kilometers.

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The correct answer that would complete the given statement above would be 59. The measurement of 0.059 seconds is equal to 59 milliseconds. To convert this, you need to know that in every 1 second, there are 1000 milliseconds. And for 1 millisecond, there is 0.001 second. 
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Gennadij [26K]

Answer:

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Is 12n2+12n+1 prime over the set of polynomials with rational coefficients? Need help ASAP
professor190 [17]

Answer:

No, the given polynomial is not prime.

Step-by-step explanation:

Given: a polynomial 12n^2+12n+1

To check: whether the given polynomial is prime or not.

Solution:

A prime polynomial is a polynomial that cannot be factored into polynomials of lower degree and has integers as coefficients.

In the given polynomial, coefficients are integers.

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3 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

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