This should be recognized as the difference of perfect squares which is of the form:
(a^2-b^2) and the difference of squares always factors to:
(a-b)(a+b) in this case:
(3x-8)(3x+8)
Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
Answer:
a = 6, b = 3, and c = 2
1. ab1 = 6 × 3 × 1 = 18
2. c + 42 = 2 + 42 = 44
3. 18 = 18
4. a − b4 = 6 - 3(4) = 6 - 12 = - 6
5. 2c3 = 2 × 2 × 3 = 12
6. b ÷ 35 = 3÷35 = 0.086
7. a − 1 6 = 6 - 16 = -10
8. 6 + c8 = 6 + 2 (8) = 6 + 16 = 22
Step-by-step explanation:
32 students in 1 row
16 students in 2 rows
8 students in 4 rows
4 students in 8 rows
2 students in 16 rows
