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Aleks04 [339]
2 years ago
14

Find all n in N that satisfy (2^n)-1 divisible by 9​

Mathematics
1 answer:
zmey [24]2 years ago
7 0

Answer:

u can use the hit and trial method for this

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Math:<br> Please help me I don’t understand and I need to do corrections.
GREYUIT [131]
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
{2}^{2}  \times 3 \times 5 \\ and \\  {2}^{2}  \times  {3}^{2}  \times 5 \times 7
each have two twos. both have one 5, so we know our answer will look something like
{2}^{2}  \times 5 \times other \: stuff
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
{2}^{2}  \times {3}^{2}  \times 5 \times stuff

what's the only number we have to deal with? 7...

how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
4 0
2 years ago
Please help me up there
Anettt [7]
The answer is 38,400

The scale is 1:40 so the side that is 4 in becomes 160 and the side that is 6 in becomes 240
Multiply 160 and 240 and that is the area of the room

Hope this helps
6 0
2 years ago
Janie walked 10 miles. Then she walked 15
Lerok [7]
The answer is letter C
5 0
2 years ago
Read 2 more answers
What is the overall charge of phosphide
Nuetrik [128]

Answer:

negatively charged

Step-by-step explanation:

4 0
2 years ago
If cos theta = -3/5 in quadrant 2, what is sin theta?
mote1985 [20]

Answer:

hello : sin(θ) = 4/25

Step-by-step explanation:

you know : cos²(θ) + sin²(θ) =1   and : cos(θ) = - 3/5

(-3/5)² + sin²(θ) =1

9/25 + sin²(θ) =1

sin²(θ) =1 -9/25

sin²(θ) = 16/25

sin(θ) = 4/25 or sin(θ) = - 4/25

in quadrant 2 :  sin(θ) > 0

so : sin(θ) = 4/25

3 0
3 years ago
Read 2 more answers
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