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Angelina_Jolie [31]
3 years ago
11

Simplify (4-3i)(5+2i)

Mathematics
1 answer:
Anna [14]3 years ago
8 0
Hey I'm probably too late but your answer would be 26-7i

Hope this helps :)
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Complete the recursive formula of the arithmetic sequence -3, -1, 1, 3,...
Strike441 [17]

Given:

The given arithmetic sequence is:

-3,-1,1,3,...

To find:

The recursive formula of the given arithmetic sequence.

Solution:

We have,

-3,-1,1,3,...

Here, the first term is -3. So, b(1)=-3.

The common difference is:

d=-1-(-3)

d=-1+3

d=2

The recursive formula of an arithmetic sequence is:

b(n)=b(n-1)+d

Where, d is the common difference.

Putting d=2, we get

b(n)=b(n-1)+2

Therefore, the recursive formula of the given arithmetic sequence is b(n)=b(n-1)+2, where b(1)=-3.

8 0
3 years ago
Can the distributive property be used to rewrite
Harman [31]

Answer:

I think No

Step-by-step explanation:

6 0
3 years ago
7. George has some quarters and some dimes. He has 6 more dimes than quarters and all of
maw [93]

Answer:

the answer will be 18 ohkay but they will eill have more dimes than quarters

6 0
3 years ago
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OMG HELP PLS IM PANICKING OMG OMG I GOT A F IN MATH AND I ONLY HAVE 1 DAY TO CHANGE MY GRADE BECAUSE TOMORROW IS THE FINAL REPOR
kherson [118]
A. You need to compare 2/5, 1/2 and 3/4
2/5= .4
1/2= .5
3/4=.75
Therefore the bucket that is 2/5 full is less than 1/2 full
8 0
3 years ago
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Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?
Alja [10]

Answer:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: (a +b)^n, n > 0

Now, the BINOMIAL EXPANSION is the expansion which  describes the algebraic expansion of powers of a binomial.

Here, (a+b)^n  = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}

or, on simplification, the terms of the expansion are:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

The above statement holds for each  n > 0

Hence, the complete expansion for the given expression is given as above.

4 0
3 years ago
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