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steposvetlana [31]
3 years ago
10

Please help me with this I'm stuck,

Mathematics
2 answers:
algol [13]3 years ago
8 0
Y = -2x -5 


why?
-2x is found since in the table the x value is 0 and the y = -2

-5 because you are adding -5 every time 

0= -2
-1 = -7
-2 = -12
-3 = -17
Papessa [141]3 years ago
5 0
C is the right answer because in this equation put the values of the third point of the table as :-

y = 5x-2
y = 5(0)-2
y = 0-2
So, y = -2
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The length of a rectangle solid is 3.0 m the width is 0.6 meter, and the height is 0.4 meter. Find, to the nearest tenth, the nu
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Answer:

0.72\,\,m^3

Step-by-step explanation:

Given:

Length of a rectangle solid = 3 m

Width of a rectangle solid = 0.6 m

Height of a rectangle solid = 0.4 m

To find: Volume of the solid

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3 years ago
Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

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