The type and number of solutions is (b) two imaginary solutions.
<h3>How to determine the type and number of solutions?</h3>
The equation is given as:
3x² + 5x + 5 = 0
A quadratic equation can be represented as:
ax^2 + bx + c = 0
Where, the discriminant (d) is
d = b^2 - 4ac
So, we have
d = 5^2 - 4 * 3 * 5
Evaluate
d = -35
The value of d is negative
This means that the equation has only imaginary solutions
Hence, the type and number of solutions is (b) two imaginary solutions.
Read more about number of solutions at
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8 1/2 times 120 times 20 3/10 = 20706
L*W*H
Hope this helps :D
Answer:
x = 4 , y = 1
Step-by-step explanation:
3x + 2y = 14 → (1)
x + y = 5 → (2)
Multiplying (2) by - 2 and adding to (1) will eliminate the y- term
- 2x - 2y = - 10 → (3)
Add (1) and (3) term by term to eliminate y
x = 4
Substitute x = 4 into (2) and evaluate for y
4 + y = 5 ( subtract 4 from both sides )
y = 1
