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jenyasd209 [6]
1 year ago
7

Use the discriminant to determine the type and number of solutions.

Mathematics
1 answer:
Nata [24]1 year ago
5 0

The type and number of solutions is (b) two imaginary solutions.

<h3>How to determine the type and number of solutions?</h3>

The equation is given as:

3x² + 5x + 5 = 0

A quadratic equation can be represented as:

ax^2 + bx + c = 0

Where, the discriminant (d) is

d = b^2 - 4ac

So, we have

d = 5^2 - 4 * 3 * 5

Evaluate

d = -35

The value of d is negative

This means that the equation has only imaginary solutions

Hence, the type and number of solutions is (b) two imaginary solutions.

Read more about number of solutions at

brainly.com/question/25275758

#SPJ1

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Step-by-step explanation:

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The number of stamps in Kelly's stamp collection is 10 less than half the number of stamps in Marks collection. Let m represent
juin [17]

Answer:

The expression is \frac{m}{2} -10=m .

Step-by-step explanation:

Given:

The number of stamps in Kelly's stamp collection is 10 less than half the number of stamps in Marks collection.

Let m represent the number of stamps in marks collection.

Now, to write an expression show the number of stamps in Kelly's collection.

Let m represent the number of stamps in Marks collection.

And the number of stamps collection of Kellys be \frac{m}{2} -10

Now, to write an expression:

According to question:

m=\frac{m}{2} -10

\frac{m}{2} -10=m

Therefore, the expression is \frac{m}{2} -10=m .

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4 years ago
The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?
denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5

All sides have the same lengths.

2. Find the slopes of all lines:

PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}

Since the slopes of PQ and RS are the same, lines PQ and RS are parallel. Since the slopes of QR and SP are the same, lines QR and SP are parallel.

The slopes \frac{4}{3} and -\frac{3}{4} have the product of

-\dfrac{3}{4}\cdot \dfrac{4}{3}=-1,

then lines are pairwise perpendicular.

This means PQRS is a square.

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4 years ago
What is negative seven twentieths plus negative two fifths?
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