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jenyasd209 [6]
1 year ago
7

Use the discriminant to determine the type and number of solutions.

Mathematics
1 answer:
Nata [24]1 year ago
5 0

The type and number of solutions is (b) two imaginary solutions.

<h3>How to determine the type and number of solutions?</h3>

The equation is given as:

3x² + 5x + 5 = 0

A quadratic equation can be represented as:

ax^2 + bx + c = 0

Where, the discriminant (d) is

d = b^2 - 4ac

So, we have

d = 5^2 - 4 * 3 * 5

Evaluate

d = -35

The value of d is negative

This means that the equation has only imaginary solutions

Hence, the type and number of solutions is (b) two imaginary solutions.

Read more about number of solutions at

brainly.com/question/25275758

#SPJ1

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Determine whether F(x)=4x^2-16x+6 has a maximum or a minimum value and find that value
Reil [10]

Answer:

f(x) has a minimum value of -10.

Step-by-step explanation:

It will have a minimum value because the coefficient of x^2 is positive.

To find its value we convert to vertex form:

f(x) = 4x^2 - 16x + 6

     = 4(x^2 - 4x) + 6

      = 4[(x - 2)^2 - 4] + 6

      = 4(x - 2)^2 - 16 + 6

      = 4(x - 2)^2 - 10.

So the minimum value is -10.

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2 years ago
A man is driving in a city that is built on a grid his car is at point S(66,17), and he needs to get to a parking lot at point T
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Step-by-step explanation:

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3 years ago
Consider all rectangles with an area of 200m^2. Let x be the length of one side of such a rectangle. Find the dimensions of a re
Katarina [22]

Answer: Answer in Photo

5 0
2 years ago
Could somebody help me with this please
sladkih [1.3K]

Answer:

x=36

Step-by-step explanation:

if PQR is isosceles then

PRQ will also equal 69 degrees

straight line = 180 degrees

so if PRQ is 69, then

PRS = 180-69

= 111 degrees

now to find x , since we have two angles within that triangle

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3 0
3 years ago
Solve these equations.<br> |x-7|=x-7
Cloud [144]

Answer:

x ≥ 7

Step-by-step explanation:

|x - 7| = x - 7

A. For each absolute, find the intervals

x - 7 ≥ 0     x - 7 < 0

     x ≥ 7           x < 7

If x ≥ 7, |x - 7| = x - 7 > 0.

If x < 7, |x - 7| = x - 7 < 0. No solution.

B. Solve for x < 7

Rewrite |x - 7| = x - 7 as

+(x - 7) = x - 7

      x - 7 = x - 7

-x + 14 = x

        14 = 2x

          x = 7

7 ≮7. No solution

C. Solve for x ≥ 7

Rewrite |x - 7| = x - 7 as

+(x - 7) = x - 7

      x - 7 = x - 7

True for all x.

D. Merge overlapping intervals

No solution or x ≥ 7

⇒ x ≥ 7

The diagram below shows that the graphs of y = |x - 7| (blue) and of y = x - 7 (dashed red) coincide only when x ≥ 7.

6 0
2 years ago
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