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Minchanka [31]
3 years ago
13

3x + 2y = 14. X + y = 5. Work put the values of x and y

Mathematics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer:

x = 4 , y = 1

Step-by-step explanation:

3x + 2y = 14 → (1)

x + y = 5 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the y- term

- 2x - 2y = - 10 → (3)

Add (1) and (3) term by term to eliminate y

x = 4

Substitute x = 4 into (2) and evaluate for y

4 + y = 5 ( subtract 4 from both sides )

y = 1

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sdas [7]

Answer:

1/4

3/8

5/8

2/5

Step-by-step explanation:

From the table :

1.)

P(9th grade) = (9th grade total / total) = 4 / 16 = 1/4

2.)

P(comedy) = (comedy total / total) = 6 / 16 = 3/8

3.)

P(not action) = 1 - P(action) = 1 - (action total / total) = (1 - 6/16) = 1 - 3/8 = 5/8

4.)

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7 0
2 years ago
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The ratio of ages of kissi and esinam is 3:5 and esinam is 3:5 The sum of ages of all 3 is 147 years.whats the age difference be
Sergio039 [100]

Answer:

48 years.

Step-by-step explanation:

Consider the complete question is "The ratio of ages of kissi and esinam is 3:5 and that of esinam and lariba is 3:5. The sum of ages of all 3 is 147 years. whats the age difference between oldest and youngest ?"

It is given that

Kissi : Esinam = 3:5 = 9:15

Esinam : Lariba = 3:5 = 15:25

So, the combined ratio is Kissi : Esinam : Lariba = 9:15:25

Let ages of Kissi, Esinam, Lariba are 9x, 15x and 25x.

Sum of ages of all 3 is 147 years.

9x+15x+25x=147

49x=147

x=3

The value of x is 3. So, the age of all three are

Kissi=9x=9(3)=27

Esinam=15x=15(3)=45

Lariba=25x=25(3)=75

Since Lariba is oldest and Kissi is youngest, therefore, the difference between their ages is

75-27=48

Hence, difference between oldest and youngest is 48 years.

8 0
3 years ago
Sixty out of 300 is how many percent out of 100
tiny-mole [99]
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makkiz [27]

Use Pythagoras theorem

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3 years ago
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Answer:

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Step-by-step explanation:

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