The sample that is being discussed in the problem can be either DNA or RNA.
DNA and RNA are both very important molecules. Both of these hold immense value in biology since they store all the vital information required for living. The basic structures of the two are quite similar; the only difference is that DNA is double-stranded while RNA has a single strand.
DNA and RNA molecules both contain a five-carbon sugar (ribose), a phosphate group, and a nitrogenous base. Except for cytosine, guanine, and adenine, the fourth part is the phosphate group that exists in both. RNA has Uracil while DNA has Thymine.
Since it has not been mentioned here what the fourth part might be, the sample might be a DNA or an RNA molecule.
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Answer:
e) unicellular, colonial, or multicellular.
Explanation:
Protists originates from the Kingdom Protoctista. They comprise of organisms that are unicellular (Amoeba) or unicellular-colonial (volvox) in nature and which have no tisssues, therefore they are at the cellular level of organization.
Examples include, Amoeba, Paramecium, Euglena, Slime mold, Kelp, Diatoms, DInoflagellates. etc.
Some of them are also considered to be multicellular eukaryotes e.g slime molds, red algae etc. Eukaryotic organisms are organisms that possess cells containing a nucleus.
Characteristics in which protists exhibit varies from one species to the other.
For example, the mode of nutrition in eukaryotic algae are autotrophic in nature, in amoeba, they are gifted with pseudopods(false feets) in which they used to engulf prey(a term known as phagocytosis) therefore making them to be heterotrophic in nature.
In protist, locomotion varies from one organism to another. For example, in Amoeba , locomotion is achieved by extending and retracting pseudopods, Euglena are flagellated in nature , hence they move with the flagella. In Paramecium that are ciliated in nature, they move by propelling their cilia. etc.
Answer:
If the frequency of the dominant allele in the pea population is 0.8, the genotype frequencies in the population would be 0.64 AA, 0.32 Aa, and 0.04 aa.
Explanation:
Hardy-Weinberg equation tells us that:
p2 + 2pq + q2
p2 is the frequency of AA plants
2pq is the frequency of Aa plants, and
q2 the frequency of aa individuals.
A allele in the population is 80%, the frequency is 0.8.
p represent the frequency of A allele. p is 0.8
Therefore calculating for q ( frequency of a allele).
p + q = 1.0
q = 1.0 − p
q = 1.0 − 0.8
q = 0.2
p = 0.8, q = 0.2.
Now we can calculate the predicted frequencies of the different genotypes, remembering that p2 is the frequency of the AA genotype, 2pq is the frequency of the Aa genotype, and q2 the frequency of aa genotype.
p2 = 0.8 x 0.8 = 0.64
2pq = 2 x 0.8 x 0.2 = 0.32
q2 = 0.2 x 0.2 = 0.04.
Thus, we would expect to see genotype frequencies of 0.64 AA, 0.32 Aa, and 0.04 aa in the pea plants.
Answer:
Explanation:
Mechanical advantage is given by the ratio of output force by input force.
= Output force = 
= Input force = 
So,
The mechanical advantage of the pulley's is .
Hello~
The answer to your question is E.
All of these traits make restriction enzymes useful.
~Hope this Helps!~
