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3 years ago

Solve (9x-4)^2=18 using the square root method

Mathematics

1 answer:

Damm [24]3 years ago

7 0

Answer:

x = 4/9 + sqrt(2)/3 or x = 4/9 - sqrt(2)/3

Step-by-step explanation:

Solve for x over the real numbers:

(9 x - 4)^2 = 18

Take the square root of both sides:

9 x - 4 = 3 sqrt(2) or 9 x - 4 = -3 sqrt(2)

Add 4 to both sides:

9 x = 4 + 3 sqrt(2) or 9 x - 4 = -3 sqrt(2)

Divide both sides by 9:

x = 4/9 + sqrt(2)/3 or 9 x - 4 = -3 sqrt(2)

Add 4 to both sides:

x = 4/9 + sqrt(2)/3 or 9 x = 4 - 3 sqrt(2)

Divide both sides by 9:

Answer: x = 4/9 + sqrt(2)/3 or x = 4/9 - sqrt(2)/3

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3 years ago

Read 2 more answers

A square is cut diagonally into two equal parts. If each part has an area of 50 cm^2, then what is the perimeter of each part?

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Answer:

30cm

Step-by-step explanation:

Given data

When are square is cut diagonally into two parts

The resulting shape is a triangle

hence the area of the square = 50+50 = 100cm^2

The length of each side of the square = √100= 10cm

likewise the diagonal of the square = 10cm

Hence the perimeter of the resulting triangle= 10+10+10= 30cm

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2 years ago