let's firstly convert the mixed fractions to improper fractions and then sum them up.
![\bf \stackrel{mixed}{2\frac{2}{8}}\implies \cfrac{2\cdot 8+2}{8}\implies \stackrel{improper}{\cfrac{18}{8}}~\hfill \stackrel{mixed}{2\frac{1}{4}}\implies \cfrac{2\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{9}{4}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{18}{8}+\cfrac{9}{4}\implies \stackrel{\textit{using the LCD of 8}}{\cfrac{(1)18+(2)9}{8}}\implies \cfrac{18+18}{8}\implies \cfrac{36}{8}\implies \cfrac{9}{2}\implies 4\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B2%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%208%2B2%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B18%7D%7B8%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%204%2B1%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B9%7D%7B4%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B18%7D%7B8%7D%2B%5Ccfrac%7B9%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%208%7D%7D%7B%5Ccfrac%7B%281%2918%2B%282%299%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B18%2B18%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B36%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B9%7D%7B2%7D%5Cimplies%204%5Cfrac%7B1%7D%7B2%7D)
Answer:
see below
Step-by-step explanation:
The graph has two parts. There is one line for x < 2. It has a slope of 1 and a y-intercept of 0.
The line for x > 2 is the horizontal line x=2.
The point at x=2 is not defined by the function you have posted here, so there is a "hole" in the graph at that point.
Answer:
4/3 pounds of sausage
Step-by-step explanation:
hope this helps... also, can u mark me as brainliest. and nice search engine. brave is my fav
The mass lost by Darragh's coin is 0.164 g
<u>Solution:</u>
Given that Darragh has a Golden Eagle coin in his collection with a mass of 13.551 g
An uncirculated Golden Eagle coin has a mass of 13.715 g
To find: mass lost by Darragh's coin
From given question,
Darrangh has coin of mass = 13.551 g
Golden Eagle coin mass = 13.715 g
Darrangh's coin lost mass = 13.715 - 13.551 = 0.164
Thus mass lost by Darragh's coin is 0.164 g
Answer:M=4
Step by step answer
9x^2-mx^2+12x-3=5x^2+12x-35
9x^2-mx^2+12x-3+3=5x^2+12x-35+3
9x^2-mx^2+12x=5x^2+12x-32
9x^2-mx^2+12x-12x=5x^2+12x-32-12x
9x^2-mx^2-5x^2=5x^2-32-5x^2
-mx^2+4x^2=-32
x^2(-m+4)=-32
M=4
Hope this helps (;
