The tangent trigonometric function is equal to the quotient of sine and cosine through the trigonometric identity. In this case, we are given with x = 9 tan (theta). Hence the answer to this problem is the expounded algebraic expression x = 9 sin (theta) / cos (theta).
The quadratic form is ax^2 + bx + c
The given equation is 6x^2 -30 = 0
a = 6 because it is with x^2.
There is no x term in the equation so b is 0
c is the numerical term with no variable so c = -30
a = 6
b = 0
c =-30
0.63 - 0.36 = 0.27 Hope this helps
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