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Kryger [21]
4 years ago
10

Find the value of x.

Mathematics
1 answer:
Gemiola [76]4 years ago
6 0

Answer:

no

Step-by-step explanation:

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2) Ten Percent of 27 is _<br> One Percent of 27 is<br> Find 14% of 27.
geniusboy [140]

Step-by-step explanation:

10%of 27

=  \frac{10}{100}  \times 27

=  \frac{27}{10}  = 2.7

1% of 27

=  \frac{1}{100}  \times 27 = 0.27

14\%of \: 27 =  \frac{14}{100}  \times 27 = 3.78

8 0
4 years ago
How to decompose 9/10 in 3 ways
egoroff_w [7]
Is this what you needed?

8 0
3 years ago
Question 1
8090 [49]

The correct answer is C. The 13 moose are the individuals. There is one categorical variable and four quantitative variables.

Explanation:

In research, the individuals refer to the participants or population that is being analyzed. For example, if the purpose of the research is to know how many hours highschool students sleep, the individuals are high school students. In this context, the individual or population of this study ae the 13 moose.

Moreover, this research focuses on different variables such as gender, height, the number of hours each moose spends in the water, the weigh of the food eaten on average by each moose, and the average weight of food eaten every day. From these variables, the last four variables are quantitative because they can be measured using numbers, for example, the height is measured in inches. On the other hand, the first variable is categorical because each moose can be classified in only two categories: male or female.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Csqrt%7B2%20-%207x%7D%20%20%2B2x%20%3D%200" id="TexFormula1" title=" \sqrt{2 - 7x} +
FrozenT [24]

Answer:

√(2 - 7x) + 2x = 0

√(2 - 7x) = - 2x

[√(2 - 7x)]² = (- 2x)²

2 - 7x = 4x²

4x² + 7x - 2 = 0

4x² + 8x - x - 2 = 0

4x(x + 2) - (x + 2) = 0

(4x - 1)(x + 2) = 0

4x - 1 = 0 => 4x = 1 => x₁ = 1/4

x + 2 = 0 => x₂ = - 2

7 0
3 years ago
How many pairs of whole numbers have a sum of 40
Step2247 [10]
An infinite number of pairs of whole numbers have a sum of 40.

6 0
4 years ago
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