At first triangle it need to be per formula AC/sin44= AB/sin53 and then you find AB=(AC×sin53)/sin44 and when you have AB you can find third angle because the summa of angels in triangle are 180 and when you have the third angle (let's call it z) you can find CB per formula CB=(AC×z)/sin44
Answer:
Step-by-step explanation:
A do-decagon is a polygon with 12 straight sides and 12 equal angles.
-The general formula for finding area of a do-decagon is given as:
where s is the sides length.
-Given the sides dimension is 9cm, the area is calculated as;
Hence, the do-decagon's area is
Sixth power of 10 (10^6) equals 10 with five extra zeros (1000000), which is nothing else but million. If you multiply it by 93, you will get the answer - the Sun is approx. 93000000 miles from Earth.
Answer:
b. The system is not in echelon form because the system is not organized in descending "stair step" pattern so that the index of the leading variables increases from the top to bottom.
Step-by-step explanation:
The given linear system has a equation which is not in echelon form. The echelon is a system which divides the data into rigid hierarchal groups. The given linear equation in not in echelon form as the leading variables are increased from top to bottom indicating descending stair step pattern.
Answer:
nope
Step-by-step explanation:
A-(b-c)=(A-b)-c
let a be 2, b be 3 and c be 4
2-(3-4)=(2-3)-4
2-(-1)=(-1)-4
2+1=-1-4
3=-5
therefore, association is not goot under subtraction
<h2>
<em><u>I </u></em><em><u>hope</u></em><em><u> that</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> and</u></em><em><u> please</u></em><em><u> mark</u></em><em><u> my</u></em><em><u> answer</u></em><em><u> as</u></em><em><u> the</u></em><em><u> brainliast</u></em><em><u> answer</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>it </u></em><em><u>would</u></em><em><u> be</u></em><em><u> an</u></em><em><u> honor</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em></h2>