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bearhunter [10]
3 years ago
6

*30 POINTS* In a group of 53 children, 22 had a dog, 18 had a cat, and 6 had both a dog and a cat. How many children had neither

a dog nor a cat as a pet?
A.)31
B.)19
C.)12
D.)37

I've been stuck on this for idk how long. Keep note that this question might be a typo, I'll update this later just in case it is.
Mathematics
2 answers:
Gnesinka [82]3 years ago
6 0

Answer:

7

Step-by-step explanation:

Although I don’t see that answer, with 53 children and 22 having a dog, 18 a cat, and 6 with both, you would think to subtract all three of those numbers with 53 to get the remaining with no dogs or cats, which results to 7

sergij07 [2.7K]3 years ago
6 0
22+18+6=46
53-46=8
Therefore 8 students did not have a dog or a cat as a pet
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Answer:

Average employee [Mean] = 43.6

Step-by-step explanation:

Given:

Interval   Number of employee

25-35                      20

35-45                      7

45-55                      8

55-65                     15

Total                       50

Find:

Average employee [Mean]

Computation:

Interval     X[u+l]/2 Number of employee   fx

25-35         30           20                              600

35-45         40             7                              280

45-55         50            8                              400

55-65         60            15                             900

Total                           50                            2,180

Average employee [Mean] = Sum of fx / Sum of x

Average employee [Mean] = 2,180 / 50

Average employee [Mean] = 43.6

5 0
3 years ago
Brittany and Ashley can paint a room in 7 hours if they work together. If Ashley were to work by himself, it would take him 2 ho
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Answer:

Step-by-step explanation:

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Ashley paints the room in x+2 hours, completing 1/(x+2) of the room per hour.

Working together, they complete 1/x + 1/(x+2) = ⅐ of the room per hour.

7(x+2) + 7x = x(x+2)

14x + 15 = x^2 + 2x

x^2 - 12x - 15 = 0

x = [12 ±√(12²+60)]/2= 6±√51

6-√51 is an extraneous solution.

x = 6+√51 ≈ 13.14

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Answer:

D. (1, -2)

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<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define systems</u>

5x - 2y = 9

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<u>Step 2: Rewrite systems</u>

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<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Add to equations together:                    13x = 13
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<u>Step 4: Solve for </u><em><u>y</u></em>

  1. Define:                              3x + 4y = -5
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  4. Isolate <em>y </em>term:                  4y = -8
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Answer:

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hope this helps

have a good day :)

Step-by-step explanation:

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