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bearhunter [10]
3 years ago
6

*30 POINTS* In a group of 53 children, 22 had a dog, 18 had a cat, and 6 had both a dog and a cat. How many children had neither

a dog nor a cat as a pet?
A.)31
B.)19
C.)12
D.)37

I've been stuck on this for idk how long. Keep note that this question might be a typo, I'll update this later just in case it is.
Mathematics
2 answers:
Gnesinka [82]3 years ago
6 0

Answer:

7

Step-by-step explanation:

Although I don’t see that answer, with 53 children and 22 having a dog, 18 a cat, and 6 with both, you would think to subtract all three of those numbers with 53 to get the remaining with no dogs or cats, which results to 7

sergij07 [2.7K]3 years ago
6 0
22+18+6=46
53-46=8
Therefore 8 students did not have a dog or a cat as a pet
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The diameter is 3 feet. Substitute this into the equation:

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Question 13 (3 points)
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Answer:

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4 0
3 years ago
A certain brand of coffee costs $2.99 for 11.3 ounces. What is the unit rate? Enter your answer, rounded to the nearest cent, in
Marysya12 [62]
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Marsh
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3 years ago
Read 2 more answers
Someone plz help me out
Musya8 [376]

Answer:

The correct answer is B) - 1/6

Step-by-step explanation:

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NNADVOKAT [17]

Answer:

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Step-by-step explanation:

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we can make --8 to positive 8

so:

y+8=-2(x-4)

this is the equation in point-slope form

Hope this helps!

4 0
3 years ago
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