Is the letter c is the anwers
We are given that the
operation of all circuits is independent with each other, therefore we can use
the multiplication rule for independent events, which states that P (intersection
of A and B) = P(A) * P(B). In this case, we want the intersection of circuit 1 to
be working with the intersection of circuit 2 on and on until circuit 40. That
is, we want every circuit to work with each other. The given probability that
circuit 1 works is .99. The probability that circuit 2 works is still .99 since
this is independent events. And we see that the probability for each of the 40
circuit to work is .99. <span>
So P (intersection of 1 through 40) = .99 * .99 *
.99.....*.99 = (.99)^40 = .6689717586</span>
Answer:
<span>There is a 0.67 probability
(or 67%) that the product will work.</span>
Let x represent some number
Sum of 3 and twice some number = 3 +2x
Five times the sum of 3 and twice some number: 5(3+2x)
5(3+2x)=70
15+10x=70
Subtract 15 from both sides to have 10x by itself
10x=55
Divide 10 on both sides to get x by itself
x=55/10
x=5.5
Hope this helped
Answer:
b
Step-by-step explanation:
Answer:
x < 25
Step-by-step explanation: