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allochka39001 [22]

3 years ago

14

What is 10.44 rounded to the nearest tenth?

1 answer:

notka56 [123]3 years ago

6 0

The answer would be 10.4 since u wanted 10.44 rounded to nearest ''tenths'' that would be 1 decimal so basically move one decimal from the right to the left and u get 10.4.

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Ln (x-2) +ln (2x-3)=2ln x

goblinko [34]

$D:x-2\ \textgreater \ 0 \wedge 2x-3\ \textgreater \ 0 \wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2 \wedge x\ \textgreater \ \dfrac{3}{2}\wedge x\ \textgreater \ 0\\
D:x\ \textgreater \ 2\\\\
\ln (x-2) +\ln (2x-3)=2\ln x \\
\ln (x-2)(2x-3)=\ln x^2\\
(x-2)(2x-3)=x^2\\
2x^2-3x-4x+6=x^2\\
x^2-7x+6=0\\
x^2-x-6x+6=0\\
x(x-1)-6(x-1)=0\\
(x-6)(x-1)=0\\
x=6 \vee x=1\\
1\not \in D\\
\boxed{x=6}$

4 0

3 years ago

I need help his to do it

11111nata11111 [884]

The answer is 150 cm²

3 0

3 years ago

Read 2 more answers

suzy had 10L of water. She wanted to pour an equal amount of water into 5 thermoses. How many liters did she pour into each ther

Liula [17]

She poured 2L into each.

10 / 5 = 2

8 0

3 years ago

Read 2 more answers

2<-1t<br> line under the

oksano4ka [1.4K]

Assuming we are solving for t
2<-1t
3

5 0

3 years ago

What is the y-intercept of this function?<br> f(x) = 2(x - 7)2 – 32

LUCKY_DIMON [66]

We are given the following function and want to find the y-intercept:

$f(x)=2(x-7)^2-32$

Just substitute the value x=0 into the equation to find the value of the y-intercept:

$y=2(0-7)^2-32$

Simplify

$=2(49)-32$

Simplify again

$=66$

Since the value of f(x), or y, when x=0 is 66, the y-intercept of this function is 66.

Let me know if you need any clarifications, thanks!

~ Padoru

4 0

3 years ago