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3 years ago

A dimensionless quantity

Mathematics

1 answer:

neonofarm [45]3 years ago

8 0

A.) A dimensionless quantity never has a unit...

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Can the sides of a triangle have lengths 1, 7, and 11? Explain

Airida [17]

Given 3 sides of a triangle, the sum of any 2 sides must be greater than the third side.

Consider the 3 given sides 1, 7 and 11

7 + 11 = 18 > 1

1 + 11 = 12 > 7

1 + 7 < 11 ⇒ not valid

Hence these sides do not form a triangle

6 0

3 years ago

How can you isolate the variable x on one side of an inequality

Tcecarenko [31]

you combine like terms first.

for example: 2x=2+5

add up the two plus 5 so that will give you seven then you're going to divide 2 by 7 so that you isolate the x and you'll get your answer.

8 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

4 years ago

Read 2 more answers

. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).

devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = $\frac{360}{n}$

Therefore, angle at the center of a dodecagon = $\frac{360}{12}$ = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = $\frac{1}{2}.(a).(b).sin\theta$

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = $\frac{1}{2}.(3).(3).sin30$

= $\frac{9}{4}$

Area of dodecagon = 12×area of the small triangle

= 12× $\frac{9}{4}$

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0

3 years ago

Two tanks are shown below. Both are filled to capacity, but the owner decides to drain them. Tank 1 is draining at a rate of 8 l

Firlakuza [10]

Answer:

Tank 2

Step-by-step explanation:

Tank 2 has more water coming out at a faster rate.

5 0

3 years ago

Read 2 more answers