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Kazeer [188]
3 years ago
6

Ax + b = c for c What is the answer to that ^

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

c = ax + b

Step-by-step explanation:

Rewrite it

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Please help!! asap!!!
Lubov Fominskaja [6]

Solution:

Rewrite 3 ≥ y - 2 for easier calculation:

y - 2 ≤ 3

Move the term:

y ≤ 3 + 2

y ≤ 5

When graphing the solution, filled dot (black arrow) is used for ≤ and ≥ while empty dot (white arrow) is used for < >

6 0
2 years ago
7. ***HINT: MEAN = AVERAGE *
Korolek [52]
The mean is 4.9 miles per day
3 0
3 years ago
Students were packed shoulder to shoulder in a gym for a pep rally. The students were in a rectangular shaped area of 7,500 ft2.
hram777 [196]

Answer: 1527

Step-by-step explanation:

Total Area = 7500 ft^2

Area covered by one student = Area of one circle

                                                   = π*r^2

r = radius of circle = 2.5/2 = 1.25 ft

Area covered by one student = π*1.25^2 = 4.91 ft^2

Number of students who can fit into total area = Total Area/Area covered by one student

Number of students who can fit into total area = 7500/4.91 = 1527.49

Hence the answer is 1527 students

7 0
3 years ago
Determine the range for the table.
Sladkaya [172]

Answer:

And the range is all real numbers except 0. The definition of range is the set of all possible values that the function will give when we give in the domain as input.

Step-by-step explanation :D give brainly

6 0
3 years ago
Question 8 of 10
Andreyy89

Median and IQR are the most appropriate measures of center and spread for this data set.

<h3>Why are Median and IQR the most appropriate?</h3>

Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:

  • Mean is affected by extreme values
  • Mean is not correct if more outliers are present
  • Mean may not represent the nature of the data whether skewed right or left.

Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,

Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.

Therefore, Option B is correct.

Read more about measures of center

brainly.com/question/10610456

#SPJ1

5 0
1 year ago
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