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Let's let
<u>x = the number of chef salads, x>=0</u>
<u>y = the number of Caesar salads, y>=0</u>
The constrains are:
40 <= x <= 60
35 <= y <= 50
x + y <= 100
The objective function here is F(x, y) = 0.75x + 1.20y
The corner points are (40, 35), (60, 35), (60, 40), (50, 50) and (40, 50).
F (40, 35) = 0.75*40 + 1.20*35 = $72
F (60, 35) = 0.70*60 + 1.20*35 = $84
F (60, 40) = 0.75*60 + 1.20*40 = $93
F (50, 50) = 0.75*50 + 1.20*50 = $97.50
F (40, 50) = 0.75*40 + 1.20*50 = $90
Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.
Answer:
The exact value is -3f
Step-by-step explanation:
<em>5.</em> Input 5 where the x's, 3 = 2(5) - 7 is a true statement. 10 - 7 = 3
3 < 10 - 9 is a false statement, 3 > 1 is a true statement
2 is less than or equal to 11, is a false statement (2 is less than 11, but not equal to)
18 = 30 -12 is a true statement 30 - 12 = 18, 18=18
3= 2 + 5 is a false statement, 3 is not equal to 7
<em>6. </em>7 is less than or equal to 5(4) -16, 20 - 16 = 4, 7 is not less than or equal to 4. Therefore, 4 is not a solution.
<em>7. </em>9(5) - 3 < 60, 45-3 < 60, 42 < 60, 42 is less than 60, so the equation is true.
9(6) - 3 < 60, 54 - 3 < 60, 51 < 60, 51 is less than 60, so the equation is true.
6(7) - 3 < 60, 63 -3 < 60, 60 < 60, 60 is equal to 60, the equation is false.