Answer:
70
Step-by-step explanation:
Substitute x with -6:
2(-6)²-2
2(36)-2
72-2
70
Answer:
h(t) = -16t2 + 144
h(1) = -16(12) + 144 = 128 ft
h(2) = -16(22) + 144 = 80 ft
h(2) - h(1) = 80 - 128 = -48 ft
It fell 48 ft between t = 1 and t = 2 seconds.
It reaches the ground when h(t) = 0
0 = -16t2 + 144
t = √(144/16) s = 3s
It reaches the ground 3s after being dropped.
Step-by-step explanation:
You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
1. False
2. True
3. True
Step-by-step explanation:
Remark
The point of this question is to encourage you to make use of your calculator. Every calculator can find square roots as far as I know.
Givens
= 8.367
= 8.49
= 8.77
One
Point A is roughly 8.15. The square root of 70 is over 8.3 So square root 70 is to the right of point A. False.
Two
Square root 72 is 8.49. B is 8.3 and C is 8.6. The statement is True
Three
sqrt(77) = 8.77. Point D is 8.75. The answer is true, but I wouldn't want to bet money on it. The difference is slightly less than 2 100s.
Answer:
What is the simplified form of this expression?
7a2 + 10a − 3a − 2a2
Step-by-step explanation:
7a2 + 10a − 3a − 2a2
Combine like terms
742 + 10a - 3a - 2a2
742 + 7a - 2a2
solution=
5a2 + 7a
