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serg [7]
3 years ago
10

on thursday, a local hamburger shop sold a total of 388 hamburgers and cheeseburgers. The number of cheeseburgers sold was bree

times the number of hamburgers sold. How many hamburgers were sold on Thursday?
Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0

There were 97 hamburgers sold on Thursday

Step-by-step explanation:

The given is:

  • On Thursday, a local hamburger shop sold a total of 388 hamburgers and cheeseburgers
  • The number of cheeseburgers sold was three times the number of hamburgers sold

We need to find how many hamburgers were sold on Thursday

Assume that the number of hamburgers was sold is x

∵ The number of hamburgers sold is x

∵ The number of cheeseburgers sold was three times the number

   of hamburgers sold

- Multiply x by three to get the number of the cheeseburger

∴ The number of cheeseburger sold is 3x

∵ The shop sold a total of 388 hamburgers and cheeseburgers

- Ad x and 3x, then equate the sum by 388

∴ x + 3x = 388

- Add like terms in the left hand side

∴ 4x = 388

- Divide both sides by 4

∴ x = 97

There were 97 hamburgers sold on Thursday

Learn more:

You can learn more about the equations in brainly.com/question/11306893

#LearnwithBrainly

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8 0
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A pathologist knows that 14.9% of all deaths are attributable to myocardial infarctions (a type of heart disease). (Either you h
garik1379 [7]

Answer:

a) The mean number is 745 and the standard deviation is 25.18.

b) 896 deaths is a significantly high number, which means that there is cause for concern.

Step-by-step explanation:

For each death, there are only two possible outcomes. Either it is attributable to myocardial infarctions, or it is not. The probability of a death being attributable to myocardial infarctions is independent of other deaths. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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In this problem:

p = 0.149, n = 5000

a. Find the mean and standard deviation for the number of such deaths that will occur in typical region with 5000 deaths.

E(X) = np = 5000*0.149 = 745

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5000*0.149*0.851} = 25.18

The mean number is 745 and the standard deviation is 25.18.

b. In one region, 5000 death certificates are examined, and it is found that 896 deaths were attributable to myocardial infarction. Is there cause for concern? Why or why not?

Is 896 a significantly high number?

E(X) + 2\sqrt{V(X)} = 745 + 2*25.18 = 795.36

895 > 795.36

896 deaths is a significantly high number, which means that there is cause for concern.

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