Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
2/11 because there is 11 letters which would be the denominator and then there is 2 I's which would be the numerator
Tamer earns <em>0.5 AED</em> per newspaper, since the slope of this line is 0.5/1
Question for ya.... what is AED? American Express Dollars?
Answer: 50m
Step-by-step explanation:
this is the logical way I solved it:
1. Find the area of the entire area thing
300*200=60000
2. Subtract the area of the field from the area of the entire place
60000-30000=30000
3. Divide the area of the parking by three because there are three sides
30000 ÷ 3 = 10000
4. Divide 10000 by 200, not 300 because we want to find the side with one <em>x</em>, not two <em>x</em> (there are two sides adding on to the side with 300, but only one side on the side with 200)
10000÷200= 50
I know the steps are weird, but I know this is the right answer because this was on the unit test (same misspelling and everything lol) and during tutoring my teacher showed me how to do it, but of course I had to forget the steps.
