Answer:
Please take a picture and ask it again, it had failed to access it.
Where is the model on the question ?
1) 1 + 1 = 2
2) 1 - 1 = 0
3) 1 * 1 = 1
4) 1 / 1 = 1
Hope this helps!
Answer:
Hi how are you doing today Jasmine
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).
b. True. Suppose

is the matrix of the eigenvectors of

, and

is the diagonal matrix of the eigenvalues of

:


Then

In other words, the columns of

are

, which are identically

, and these are the columns of

.
c. False. A counterexample is the matrix

which is nonsingular, but it has only one eigenvalue.
d. False. Consider the matrix

with eigenvalue

and eigenvector

, where

. But the matrix can't be diagonalized.