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Veronika [31]
3 years ago
9

Find each number. Round to the nearest tenth if necessary

Mathematics
1 answer:
Pavel [41]3 years ago
6 0

Answer:

  1. 96
  2. 6.9
  3. 25%
  4. 8%
  5. 79
  6. 33.8

Step-by-step explanation:

Here is the complete question: Find each number. Round to the nearest tenth if necessary.

  1. 80% of 120.
  2. 115% of 6
  3. What percent of 128 is 32?
  4. 3 is what percent of 36?
  5. 23.7 is 30% of what number?
  6. 71/2% of what is 12?

1) 80% of 120

= \frac{80}{100} \times 120= 8\times 12

= 96

∴ 80% of 120= 96

2) 115\%\ of\ 6

=\frac{115}{100}\times 6= 1.15\times 6

∴ 115\%\ of\ 6 = 6.9

3) What percent of 128 is 32?

= \frac{32}{128} \times 100

= 25\%

4) 3 is what percent of 36?

= \frac{3}{36} \times 100

= 8\%

5) 23.7 is 30% of what number?

Let the number be "x".

⇒ \frac{30}{100} \times x= 23.7

Cross multiplying

⇒ x= \frac{23.7\times 100}{30}

∴ x= 79.

6) 71/2% of what is 12?

Lets assume the required number be "x".

⇒ \frac{71}{2} \times 100\times x= 12

cross multiplying both side.

⇒x= 33.8

∴ 71/2% of 33.8 is 12

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The rectangular bar is connected to the support bracket with a 10-mm-diameter pin. The bar width is w = 70 mm and the bar thickn
german

Answer:

P_max = 9.032 KN

Step-by-step explanation:

Given:

- Bar width and each side of bracket w = 70 mm

- Bar thickness and each side of bracket t = 20 mm

- Pin diameter d = 10 mm

- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa

- Average allowable shear stress of pin S = 115 MPa

Find:

The maximum force P that the structure can support.

Solution:

- Bearing Stress in bar:

                                       T = P / A

                                       P = T*A

                                       P = (120) * (0.07*0.02)

                                       P = 168 KN

- Shear stress in pin:

                                        S = P / A

                                        P = S*A

                                        P = (115)*pi*(0.01)^2 / 4

                                        P = 9.032 KN

- Bearing Stress in each bracket:

                                       T = P / 2*A

                                       P = T*A*2

                                       P = 2*(120) * (0.07*0.02)

                                       P = 336 KN

- The maximum force P that this structure can support:

                                      P_max = min (168 , 9.032 , 336)

                                      P_max = 9.032 KN

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Answer:

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Step-by-step explanation:

24a²b³ - 28a⁵b³

apply exponential rule:

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re-write 24 as 6*4    and  -28 as 7*4

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