Answer:
So since the ball is at x=0 at the end.
We plug in it.
h(x) = 16 if you simplify it
In this scenario we know that carbon14 at a given time A(t) = A0e^(-kt), where A0 is the original carbon present, t is time in years and k is the constant.
As we are working with the half life of carbon being 5730 years, we assume original carbon-14 content, A0 = 1, and carbon-14 at half life 5730 years, A(t) = 0.5.
i.e.
0.5 = 1e^(-5730k)
apply Ln to both sides of equation to cancel e
ln(0.5) = -5730k
k = ln(0.5) / -5730
k = -0.69315 / - 5730 = 1.20968 x 10^-4
In your figure where as ask what kind of symmetry is shown in the figure of your problem and the best answer would be reflectional symmetry. I hope you are satistfied with my answer and if you need some clarification, please feel free to ask for more
I can only list four of them:. 38, 46, 64, and 83.
8y^3+316
divide both sides by 4 (smallest divisable number) just say you tried to factor 2 and 3 and they weren't whole numbers and then you tried 4 and gave you the answer :)
4(2y^3+79)