According to order of operations rules, exponentiation must be done first. Thus, we have
(3^2)*(3^2) = (9)(9) = 81.
Alternatively, note that there's only one base (3) here, even tho' it shows up more than once. So, 3^2*3^2 = 3^(2+2) = 3^4 = 81.
Answer:

Step-by-step explanation:
<u>Ratios
</u>
We are given the following relations:
![a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%5Cqquad%20%5Cqquad%5B1%5D)
![b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B63%7D%2B%5Csqrt%7Bd%7D%5Cqquad%20%5Cqquad%5B2%5D)
![\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bc%7D%7Bd%7D%3D%5Cfrac%7B1%7D%7B9%7D%20%5Cqquad%20%5Cqquad%20%5B3%5D)
From [3]:

Replacing into [2]:

We can express 63=9*7:

Taking the square root of 9:

Factoring:

Find the ration a:b:

Simplifying:

"Since the ratio is 5:7 you can think in total there was 12 equal blocks of money invested. 5 of those blocks belonged to Jim and 7 of those blocks belonged to Gail. Since they invested $3,600 and then made $6,450 in total there is $10,050. Divide that total into 12 equal blocks of $837.50 and 5 of those blocks belong to Jim. So he will get $4,187.50"
-72-4x^2+8x^3-36x/x-3
-4(18+x^2-2x^3+9x)/x-3
-4(-2x^3+x^2+9x+18)/x-3
-4(-2x^2x(x-3)-5x x(x-3)-6(x-3) )/x-3
-4 x(-(x-3) ) x (2x^2+5x+6)/x-3
-4 x (-1) x (2x^2 +5x+6)
8x^2+20x+24
Place the decimal point right after the first nonzero digit, which is 3.
So you'll go from this

to this

after this move.
Now ask yourself: "how many spots must I move the decimal point to get back to 0.003045?"
The answer is "3 spots to the left"
The exponent of the final answer is -3
The negative indicates "move left" and the 3 tells us how many places to move the decimal
Therefore,
Answer: Choice C)This is assuming you meant to write the -3 as an exponent