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2 years ago

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Find the charge on the capacitor in an LRC-series circuit at t = 0.05 s when L = 0.05 h, R = 4 ?, C = 0.008 f, E(t) = 0 V, q(0)

= 7 C, and i(0) = 0 A.(Round your answer to four decimal places.) _______C. Determine the first time at which the chrage on the capacitor is equal to zero. (Round your answer to four decimal places.) _______s.

1 answer:

Nutka1998 [239]2 years ago

5 0

Step-by-step explanation:

Below is an attachment containing the solution.

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The question is:

kifflom [539]

Pythagoras theorem is c^2 = b^2 + a^2

so when you plug in the numbers its 12^2 + 5^2 =169
which means 144+24=169

square root 169 = 13

AB =13 cm

hope this helps I tried my best. xx

6 0

3 years ago

Change 21/4 to a mixed number

8090 [49]

Answer:

$5\frac{1}{4}$

Step-by-step explanation:

Greatest multiplier of 4 that is less than 21 is 5 (4 x 5 = 20)

Put the remaining number as the numerator (21 - 20 = 1)

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2 years ago

The deck that Amos is building is in the shape of a parallelogram, DGRY. The measure of

weqwewe [10]

Complete Question:

The deck that Amos is building is in the shape of a parallelogram, DGRY. The measure of D is five-halves the measure of Y. Find the measure of each angle of the deck.

Answer:

$\angle G = \angle Y = 51.43 ^{\circ}$

$\angle D = \angle R = 128.57 ^{\circ}$

Step-by-step explanation:

Given

Shape: Parallelogram DGRY

Dimension: $\angle D = \frac{5}{2}\angle Y$

Required

Find the measure of each angle

D and R are opposite sides & G and Y are also opposite sides.

So, we have:

$\angle D = \angle R = \frac{5}{2}\angle Y$

and

$\angle G = \angle Y$

The sum of angles is given as:

$\angle D + \angle G + \angle R + \angle Y=360^{\circ}$

Substitute values for $\angle D, \angle G \ \& \angle R$

$\frac{5}{2}\angle Y + \frac{5}{2}\angle Y + \angle Y + \angle Y = 360^{\circ}$

Take LCM

$\frac{5\angle Y + 5\angle Y + 2\angle Y+ 2\angle Y}{2}= 360^{\circ}$

$\frac{14\angle Y}{2}= 360^{\circ}$

Multiply both sides by $\frac{2}{14}$

$\frac{2}{14} * \frac{14\angle Y}{2}= 360^{\circ} * \frac{2}{14}$

$\angle Y= 360^{\circ} * \frac{2}{14}$

$\angle Y= \frac{ 360^{\circ} *2}{14}$

$\angle Y= \frac{720^{\circ}}{14}$

$\angle Y= 51.43 ^{\circ}$

So:

$\angle G = \angle Y = 51.43 ^{\circ}$

$\angle D = \frac{5}{2}\angle Y$

$\angle D = \frac{5}{2} * 51.43^{\circ}$

$\angle D = \frac{5* 51.43^{\circ}}{2}$

$\angle D = \frac{257.15^{\circ}}{2}$

$\angle D = 128.57 ^{\circ}$

Hence:

$\angle D = \angle R = 128.57 ^{\circ}$

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2 years ago

NEED HELP, LIMITED TIME, HURRY

11111nata11111 [884]

Answer:

9

Step-by-step explanation:

here you go!

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3 years ago

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Using the function A(t)=P(1=r/n)^nt, create the function that represents your new car loan that is compounded monthly. The princ

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3 years ago