Find the charge on the capacitor in an LRC-series circuit at t = 0.05 s when L = 0.05 h, R = 4 ?, C = 0.008 f, E(t) = 0 V, q(0)
= 7 C, and i(0) = 0 A.(Round your answer to four decimal places.) _______C. Determine the first time at which the chrage on the capacitor is equal to zero. (Round your answer to four decimal places.) _______s.
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Answer:
Step-by-step explanation:
Ok, so first substitute x for 4 in
"g(x) = 5x + 1", and x for 3 in
"k(x) = 2/x + 2x". Now you got:
g(4) = 5(4) + 1
k(3) = 2/(3) + 2(3)
Now you can solve each individually.
g(4) = 5 × 4 = 20
20 + 1 = 21
g(4) = 21
k(3) = 2 × 3 = 6
6 + 2/3 = 6 2/3
k(3) = 6 2/3
g(4) + k(3) = 21 + 6 2/3 = <u>27 2/3</u>
Hope this helps :)