Please help me solve the answer for this question

⚠️WILL GIVE BRAINLIEST⚠️

seropon [69]

Answer:

It's letter C (x = -2) (y = 1)

Step-by-step explanation:

3 0

2 years ago

An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a

dsp73

Answer:

P(X=0)=0.000008

P(X=1)=0.00176

P(X=2)=0.057624

P(X=3)=0.941192

Step-by-step explanation:

Probability of correct classification = p = 0.98

Probability of incorrect classification = q = 1 - p = 0.02

The probability of success and failure is the same for all the trials. The trials are independent of each other and the number of trials is fixed i.e. n = 3.

This satisfies all the conditions of a Binomial Experiment. So we can use Binomial experiment to model the probability mass function.

The general formula of a binomial probability is:

$P(X=x)=^{n}C_{x}(p)^{x}q^{n-x}$

Here x denote the number of successes, which can be {0, 1, 2, 3}. So we need to evaluate the above equation for each value of x to determine the probability Mass function of X, as shown below:

$P(X=0)=^{3}C_{0}(0.98)^{0}(0.02)^{3-0}=0.000008\\\\ P(X=1)=^{3}C_{1}(0.98)^{1}(0.02)^{3-1}=0.001176\\\\ P(X=2)=^{3}C_{2}(0.98)^{2}(0.02)^{3-2}=0.057624\\\\ P(X=3)=^{3}C_{3}(0.98)^{3}(0.02)^{3-3}=0.941192$

7 0

2 years ago

Look at this graph:

Radda [10]

Use the method rise over run (rise/run) that would get you 30/20 and that would equal to 1.5

8 0

2 years ago

Read 2 more answers

a particular city had a population of 24,000 in 1900 and a population of 29,000 in 1920. Assuming that its population continues

DerKrebs [107]

Answer:

It will have a population of 61,779 in 2000.

Step-by-step explanation:

The population for the city, in t years after 1900, can be modeled by a exponential function with constant growth rate in the following format:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the population in 1900 and r is the growth rate.

Population of 24,000 in 1900

This means that $P(0) = 24000$

Population of 29,000 in 1920.

1920 is 1920 - 1900 = 20 years after 1900.

This means that P(20) = 29000. So

$P(t) = P(0)(1+r)^{t}$

$29000 = 24000(1+r)^{20}$

$(1+r)^{20} = \frac{29000}{24000}$

$\sqrt[20]{(1+r)^{20}} = \sqrt[20]{\frac{29000}{24000}}$

$1 + r = 1.0095$

So

$P(t) = P(0)(1+r)^{t}$

$P(t) = 24000(1.0095)^{t}$

What population will it have in 2000

2000 is 2000 - 1900 = 100 years after 1900. So this is P(100).

$P(t) = 24000(1.0095)^{t}$

$P(100) = 24000(1.0095)^{100} = 61779$

It will have a population of 61,779 in 2000.

4 0

3 years ago

Three candidates were running for president of a student council. Altogether, 1524 students cast a vote in the election. The sec

Leya [2.2K]

Answer:

48%

Step-by-step explanation:

The total number of votes casted = 1524 votes = 100%

Let a = votes of first place candidate

b = votes of second place candidate

c = votes of third place candidate

The second place candidate had 140 votes less than the winner

b = a - 140 votes...... Equation 1

Hence,

a = b + 140.......... Equation 2

Second place candidate has 395 votes more than the last place candidate

b = c + 395.......Equation 3

Hence,

c = b - 395......Equation 4

a + b + c = 1524 votes....... Equation 5

If a = b + 140 and c = b - 395

The number of votes by b(second place candidate ) =

b + 140 + b + b - 395 = 1524 votes

3b = 1524 + 395 - 140

3b = 1779

b = 1779/3

b = 593 votes.

Therefore, the second place candidate had 593 votes.

Now we can calculate how many votes, the other candidates had.

The second place candidate had 140 votes less than the winner

Votes for the winner( first place candidate)

b = a - 140 votes...... Equation 1

Hence,

a = b + 140.......... Equation 2

Since b = 593

a = 593 + 140

a = 733 votes

Votes for the last place candidate

Since, Second place candidate has 395 votes more than the last place candidate

b = c + 395.......Equation 3

Hence,

c = b - 395......Equation 4

b = 593

c = 593 - 395

c = 198

From the above calculation,

a = votes of first place (winner) candidate = 733

b = votes of second place candidate = 593

c = votes of third(last) place candidate = 198

In the above question, we were asked to calculate the percentage of all the votes cast were received by the winner.

This is calculated as

= Voted received by winner/ Total number of votes casted × 100

= 733/1524 × 100

= 48.09711286%

Approximately to the nearest percent = 48%

Therefore, the percentage of all the votes cast were received by the winner = 48%

5 0

3 years ago