Answer:
p-q= -4
p=q-4
x^2 + px + q=0
=> x^2 + (q-4)x + q = 0
d= b^2-4ac
=(q-4)^2 - 4(1)(q)
= q^2 + 16 -8q - 4q
=q^2 -12q+16
given that D=16
q^2 -12q+16 = 16
=> q^2 -12q = 0
=> q^2 = 12q
=> q = 12q/q
=> q= 12
Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8
Hope you understood............
Answer:
The answer is the top right one since the total $96.35 is on the deposit side.
( i did this before and got it right btw)
Answer:
the answer is c = (ad)/b
Step-by-step explanation:
See the picture
The graph would intercept at (0,-4) on the y-axis & at (5.3,0) on the x-axis. And the shaded region would be on the right side of the line on the graph.
Use substitution
-x + 4 = 1/3x + 8
4 = 4/3x + 8
-4 = 4/3x
x = -4 * 3/4
x = -3
Then plug x into one of the original equations. In this case y = -x + 4 is the easiest.
y = -(-3) + 4
y = 7
