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3 years ago

Which of the following would justify step 6?

Mathematics

1 answer:

KengaRu [80]3 years ago

3 0

Answer: C) SAS

Explanation:

We have AD = DB which forms the first "S" in "SAS"

The second "S" is CD = CD

The angles between the two pairs of sides mentioned are the right 90 degree angles, which is what the "A" in "SAS" represents.

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A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

3 years ago

Naglakad si Ruben ng 900 sentimetro samantalang si Jaime ay naglakad ng

Gelneren [198K]

Sagot:

100 cm

Hakbang-hakbang na paliwanag:

Kung ganoon :

Distansya na sakop ng Ruben = 900 centimetri

Distansya na sakop ng Jamie = 10 metro

Pagko-convert sa centimeter:

100 cm = 1 m

x cm = 10 m

Paggamit ng multiplikasyon ng krus:

x = 100 * 10

x = 1000 cm.

Dahil dito Distansya ni Jamie = 1000 cm

Distansya sa pagitan ng Jamie at Ruben;

1000 cm - 900 cm = 100 cm

3 0

2 years ago

Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.

olya-2409 [2.1K]

Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(

7 0

3 years ago

Read 2 more answers

Sanjay read 56 pages of his book this weekend.This is 35% of the pages in the book.How many pages are in Sanjays book?

Maurinko [17]

1. 56 : 35 = 1.6
2. 1.6* 100 = 160
3. The answer is 160

3 0

3 years ago

For what values of x is 12x-6 < 13x + 10

slamgirl [31]

Answer:

x > 16