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nikklg [1K]
2 years ago
5

Slope of (10,8) (2,1)

Mathematics
1 answer:
Reptile [31]2 years ago
6 0

Answer:

slope=7/8

Step-by-step explanation:

8-1/10-2= 7/8

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2 years ago
P (6,6) y=2/3x
matrenka [14]

Answer:

y = -\frac{3}{2}x+15

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

y = \frac{2}{3}x

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

y = \frac{2}{3}x

Now, we compare the given equation by standard form y = mx +c

So, slope of the line m_{1} = \frac{2}{3}, and

y-intercept c=0

We know that the slope of the perpendicular line m_{1}\times m_{2}  = -1

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{\frac{2}{3} }

m_{2}=-\frac{3}{2}

So, the slope of the perpendicular line m_{2}=-\frac{3}{2}

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

y=mx+c

Substitute point P(x_{1}, y_{1})=P(6, 6) and m = m_{2}=-\frac{3}{2}

6=-\frac{3}{2}\times 6 +c

6=-3\times 3 +c

c=6+9

c=15

So, the y-intercept of the perpendicular line c=15

Using point slope formula.

y=mx+c

Substitute m = m_{2}=-\frac{3}{2} and c=15 in above equation.

y = -\frac{3}{2}x+15

Therefore: the equation of the perpendicular line y = -\frac{3}{2}x+15

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3 years ago
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2 years ago
Read 2 more answers
Find the zeros of y = x + 6x- 4 by completing the square.
dsp73

Answer:

\large\boxed{x=-3\pm\sqrt{13}}

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\x^2+6x-4=0\qquad\text{add 4 to both sides}\\\\x^2+2(x)(3)=4\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=4+9\\\\(x+3)^2=13\Rightarrow x+3=\pm\sqrt{13}\qquad\text{subtract 3 from both sides}\\\\x=-3\pm\sqrt{13}

8 0
3 years ago
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