Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C
A linear equation is a straight line. The equation is of the type y = MX + N
The soluction of that system is Ax^2 + Bx + C = MX + N
=> Ax^2 + (B-M)x + (C-N) = 0
That is a quadratic equation.
A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.
So you must select 0, 1 and 2.
You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.
You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.
Answer: y = 
<u>Step-by-step explanation:</u>
y = ax² ; where a represents the vertical stretch
a reflection across the x-axis is represented by making the a-value negative.
Answer:
x=20
The side lengths form a 345 triple
Step-by-step explanation:
345 triangles have 3, 4, and 5 as their lengths
If we divide all of them by 4 we get..
12/4=3 and 16/4=4 that means we are missing 5
5*4=20
Answer:4/5
hope it helps
Step-by-step explanation:
