<h3> <u>Prime Factorization </u><u>method:</u></h3>
Given that √2 = 1.414
The value of (1/2)√(16200)
16200 can be written as
16200 = 2×8100
16200 = 2×2×4050
16200 = 2×2×2×2025
16200 = 2×2×2×5×405
16200 = 2×2×2×5×5×81
16200 = 2×2×2×5×5×3×27
16200 = 2×2×2×5×5×3×3×9
16200 = 2×2×2×5×5×3×3×3×3
√16200 = √(2×2×2×5×5×3×3×3×3)
√16200 = √2×(2×2)×(5×5)×(3×3)×(3×3)
√16200 = 2×5×3×3√2
√16200 = 90√2
Now,
(1/2)√16200
⇛(1/2)×90√2
⇛90√2/2
⇛45√2
⇛45×1.414
⇛63.63
<u>Answer:</u><u> </u><u>Hence</u><u>,</u> value of (1/2)√(16200) is 63.63
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Answer:
y=1/3-5/3
Step-by-step explanation:
A = k/R where A = acceleration and R = radius of the turn and k is a constant to be found.
Substituting the given values:-
10 = k / 70
k = 10*70 = 700
So the equation of the motion is A = 700 / R
When the radius is 140 the acceleration is 700 / 140 = 5 ft/sec/sec ( answer)
1. x midpoint: (-9+4)/(2) = -2
2. y midpoint: (3+7)/(2) = 5
3. The midpoint is (-2,5)
Answer:
u have to use the almighty formula
