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3 years ago

17 pounds a day equals how many grams a day

Mathematics

1 answer:

trasher [3.6K]3 years ago

6 0

17 pounds equals 7711.07 grams a day

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Find an equation of the line that is parallel to the graph of 2x+3y=5 and contains the point (3, −1).

uranmaximum [27]

Answer:

A) Equation of line is 3X - 2Y = 11

B) Equation of line is Y = X + 1

C) Equation of line is Y - 7 = 0

Equation of line , point (3 , -1) and slop $\frac{3}{2}$ is 3X - 2Y = 11

Step-by-step explanation:

Given equation of line as 2x + 3y = 5

slove of this line (m1) = - $\frac{2}{3}$

Now another line passes through point (3 , -1) having slop (m2)

Both lines are parallel to each other, i.e (m1) × (m2) = - 1

So slop of second line (m2 ) = $\frac{-1}{m1}$

(m2) = $\frac{-1}{(\frac{-2}{3} } )$

(m2) = $\frac{3}{2}$

Now eq of line with point (3 , -1) and slop (m2)

Y- y1 = (m2)( X - x1)

Or, Y +1 = $\frac{3}{2}$ (X - 3)

i.e 2Y + 2= 3X - 9

∴ Equation of line is 3X - 2Y = 11 Answer

B) Given points as ( 5,6) and (3 , 4)

Slop (m) = $\frac{y2 - y1}{x2 - x1}$ = $\frac{4 - 6}{3 - 5}$ = 1

So the equation of line is

Y- y1 = (m)( X - x1)

Y - 6 = (1) (X - 5)

i.e Equation of line is Y = X + 1 Answer

C) Given points as ( 0, 7) , (0 , -8)

Slop (m) with co-ordianate = $\frac{y2 - y1}{x2 - x1}$

Or, = $\frac{-8 - 7}{0 - 0}$

Hence equation of line is Y - 7 = 0 Answer

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3 years ago

A dwarf sea horse swims at a rate of 50.68 feet per hour. Convert this speed to inches per minute.

egoroff_w [7]

Answer:

36489.6

Step-by-step explanation:

pls mark brainliest!

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3 years ago

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A car starts at rest and accelerates for 8 s at a rate of 3 m/s ^ 2 What is the final velocity of the car?

Bumek [7]

8m/2.6. Wisehehehbehehehdhudur

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3 years ago

Write the equation of the quadratic given the following information:

xenn [34]

<span>y=a((x-h)^2)+k
Vertex=(h,k)
1. Vertex (5,-1) Point (2,4)
y=a((x-5)^2)+(-1)
f(2)=4
4=a((2-5)^2)+(-1)
4=a(-3)^2-1
4=a*9-1
5=a*9
5/9=a
y=(5/9)((x-5)^2)-1
2. Vertex (-2,0) Point (-1,-7)
y=a((x+2)^2)+0
y=a((x+2)^2)
f(-1)=-7
-7=a(-1+2)^2
-7=a(1)^2
a=-7
y=-7(x+2)
(x-h)^2=4(d)(y-k)
3. Vertex (0,0) Focus (0,2)
d=f-v
d=2
(x^2)=4(2)(y)
(x^2)=8y
f(0)=0
4. Focus (-3,4) Directrix y= -2
(x-h)^2=4(d)(y-k)
d=(4-(-2))/2=6/2=3
(x-h)^2=4(3)(y-k)
h=-3
k=(-2+4)/2=(2)/2=1
(x+3)^2=4(3)(y-1)
(x+3)^2=12(y-1)</span>

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4 years ago

Find the slope of the line that passes through (10, 3) and (1, 10).

tatyana61 [14]

Answer: -7/9

Step-by-step explanation:

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3 years ago

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