All categories

3 years ago

Simplify 10x-4-2x+19

Mathematics

2 answers:

borishaifa [10]3 years ago

7 0

8x - 23 because you answer them until you have it all simplified

cestrela7 [59]3 years ago

5 0

The simplified equation would be 8x + 15

You might be interested in

EXAMPLE 2 Prove that 9ex is equal to the sum of its Maclaurin series. SOLUTION If f(x) = 9ex, then f (n + 1)(x) = for all n. If

amm1812

Answer:

To Prove: $9e^x$ is equal to the sum of its Maclaurin series.

Step-by-step explanation:

If $f(x) = 9e^x$ , then $f ^{(n + 1)(x)} =9e^x$ for all n. If d is any positive number and |x| ≤ d, then $|f^{(n + 1)(x)}| = 9e^x\leq 9e^d.$

So Taylor's Inequality, with a = 0 and M = $9e^d$ , says that $|R_n(x)| \leq \dfrac{9e^d}{(n+1)!} |x|^{n + 1} \:for\: |x| \leq d.$

Notice that the same constant $M = 9e^d$ works for every value of n.

But, since $lim_{n\to\infty}\dfrac{x^n}{n!} =0 $ for every real number x$$ ,

We have $lim_{n\to\infty} \dfrac{9e^d}{(n+1)!} |x|^{n + 1} =9e^d lim_{n\to\infty} \dfrac{|x|^{n + 1}}{(n+1)!} =0$

It follows from the Squeeze Theorem that $lim_{n\to\infty} |R_n(x)|=0$ and therefore $lim_{n\to\infty} R_n(x)=0$ for all values of x.

$THEOREM\\If f(x)=T_n(x)+R_n(x), $where $T_n $is the nth degree Taylor Polynomial of f at a and $ lim_{n\to\infty} R_n(x)=0 \: for \: |x-a|$

By this theorem above, $9e^x$ is equal to the sum of its Maclaurin series, that is,

$9e^x=\sum_{n=0}^{\infty}\frac{9x^n}{n!}$ for all x.

6 0

3 years ago

A cookie recipe calls for 1 cup of white sugar and 3 cups of brown sugar

Pie

Is there anythin to solve in this problem? You are not saying a question. So how can I answer it.

7 0

3 years ago

6.4 × 10^{3} [/tex] + 1.4 × 10^{4} [/tex] + 7.5 × 10³= ?

Gennadij [26K]

6.4 x 10^3 = 6400
1.4 x 10^4 = 14000
7.5 x 10^3 = 7500
total = 6400 + 14,000 + 7500
total = 27900 or 2.79 x 10^4 <===

8 0

4 years ago

(giving brainiest and all my points!!)

Vikki [24]

Answer:

1. 62

2. 13

3. 6

4. 18

5. 3

Step-by-step explanation:

1. Let's use pemdas

16*1/2= 8

32 / 4 * 8 - 2

8*8 - 2

64 - 2

= 62

2. Let's use pemdas

5*2/5 = 2

20 / 2 + 3

10 +3

= 13

3. Let's use pemdas

1/2 * 24 / 3 +2

12 / 3 +2

4 +2

4. Let's use pemdas

2 * (6 / 2 + 8) -4

2 * 11 - 4

22 - 4

= 18

5. Let's use pemdas

(28 / 7 +6 / 3) * 1/2

( 4 + 2) *1/2

6 *1/2

= 3

8 0

3 years ago

Read 2 more answers

Determine the amplitude and period of each function without graphing.

Luba_88 [7]

Answer:

Step-by-step explanation:

We know for a function:

y = Asinωt

=> on comparison, <u>A = 5 m</u>

=> T = 2π / ω

=> T = 2π / 2

=> <u>T = π seconds</u>

5 0

2 years ago