If we break down the problem if basically gives the answer:
five times the quotient of some number and ten
5 times (any variable) divided by 10
The answer is B. The answer isn't A because you have to go in order of what the question states. It didn't say ten first. It can't be C or D because those are not quotients.
The feasible region is shown in the picture above. The horizontal axis is the X axis.
If you now draw a family of lines parallel to 
through the region, increasing $C$, that is, the X-intercept, we will have the maximum value of $C$ when the line passes through the endpoint $(-2,6)$ .
Hence, $C=5(-2)+4(6)=14$
Answer:
sin60+cos30
Step-by-step explanation:
[tex] \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} \\ \\ \frac{2 \sqrt{3} + 2 \sqrt{3} }{4} \\ \frac{4 \sqrt{3} }{4 } \\ \sqrt{3} [tex]
Angle 146 = angle2 .......[Corresponding angle]
Therefore, Angle 2 = 146
Now,
Angle 5 = angle2……………[vertically opposite angle]
Therefore, angle 5 = 146
Answer:
domain x range y
Step-by-step explanation:
hopefully it helps
